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2. ) Find the area of the indicated region under the standard normal curve. -1.30 to the right. A: 0.9032

3. Find the area of the indicated region under the standard normal curve. -0.45/2.11 middle A: 0.6562

4. Find the area of the indicated region under the standard normal curve. -1.13/2.03 left/right A: 0.1504

5. Find the area under the standard normal curve to the left of z = 1.5. A: 0.9332

6. Find the area under the standard normal curve to the left of z = 1.25 A: 0.8944

7. Find the area under the standard normal curve to the right of z = 1 A: 0.1587

8. Find the area under the standard normal curve to the right of z = -1.25. A: 0.8944

9. Find the area under the standard normal curve between z = 0 and z =3. A: 0.4987

10. Find the area under the standard normal curve between z = 1 and z = 2 A: 0.1359

11. Find the area under the standard normal curve between z = -1.5 and z = 2.5 A: 0.9270

12. Find the area under the standard normal curve between z = 1.5 and z = 2.5 A: 0.0606

13. Find the area under the standard normal curve between z = -1.25 and z = 1.25. A: 0.7888

14. Find the sum of the areas under the standard normal curve to the left of z = -1.25 and to the right A: 0.2112

**Find the probability of z occurring in the indicated region

29. picture 1.82 A: 0.9656

30. picture -0.59 A: 0.2776

31. picture -1.33 A: 0.9082

32. picture 1.75 A: 0.0401

33. picture -2/3 A: 0.9772

34. picture 1.50 A: 0.4332

35. Use the standard normal distribution to find P(0 < z < 2.25). A: 0.4878

36. Use the standard normal distribution to find P(-2.25 < z < 0). A: 0.4878

37. Use the standard normal distribution to find P(-2.25 < z < 1.25). A: 0.8822

38. Use the standard normal distribution to find P(-2.50 < z < 1.50). A: 0.9270

39. Use the standard normal distribution to find P(z < -2.33 or z > 2.33) A: 0.0198

40. For the standard normal curve, find the z-score that corresponds to the third quartile. A: 0.67

41. For the standard normal curve, find the z-score that corresponds to the first quartile. A: -0.67

42. For the standard normal curve, find the z-score that corresponds to the first decile. A: -1.28

43. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An
individualʹs IQ score is found to be 110. Find the z-score corresponding to this value. A: 0.67

44. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An
individualʹs IQ score is found to be 90. Find the z-score corresponding to this value A: -0.67

45. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An
individualʹs IQ score is found to be 120. Find the z-score corresponding to this value A: 1.33

46. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. Find the
IQ score that corresponds to a z-score of 1.96. A: 129.4

47. IQ test scores are normally distributed with a mean of 102 and a standard deviation of 19. An
individualʹs IQ score is found to be 124. Find the z-score corresponding to this value. A: 1.16

48. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 12. An
individualʹs IQ score is found to be 127. Find the z-score corresponding to this value. A: 2.25

49. The lengths of pregnancies of humans are normally distributed with a mean of 268 days and a
standard deviation of 15 days. Find the probability of a pregnancy lasting more than 300 days. A: 0.0166

50. The lengths of pregnancies of humans are normally distributed with a mean of 268 days and a
standard deviation of 15 days. Find the probability of a pregnancy lasting less than 250 days. A: 0.1151

51. The distribution of cholesterol levels in teenage boys is approximately normal with μ = 170 and
σ = 30 (Source: U.S. National Center for Health Statistics). Levels above 200 warrant attention. Find
the probability that a teenage boy has a cholesterol level greater than 200. A: 0.1587

95. Assume that the heights of women are normally distributed with a mean of 63.5 inches and a
standard deviation of 2.5 inches. Find Q3, the third quartile that separates the bottom 75% from the top 25%. A: 65.2

96. The body temperatures of adults are normally distributed with a mean of 98.6 ° F and a standard
deviation of 0.19° F. What temperature represents the 95th percentile? A: 98.91 F

97. In a certain normal distribution, find the standard deviation σ when μ = 50 and 10.56% of the area
lies to the right of 55. A: 4

98. In a certain normal distribution, find the mean μ when σ = 5 and 5.48% of the area lies to the left of
78. A: 86

100. A tire company finds the lifespan for one brand of its tires is normally distributed with a mean of
48,400 miles and a standard deviation of 5000 miles. If the manufacturer is willing to replace no
more than 10% of the tires, what should be the approximate number of miles for a warranty?

A: 42,000