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Posted on Jun 5, 2017 in Other subjects

1. Find the area of the indicated region under the standard normal curve -1.30/0 to the left. A: 0.0968
2. ) Find the area of the indicated region under the standard normal curve. -1.30 to the right. A: 0.9032
3. Find the area of the indicated region under the standard normal curve. -0.45/2.11 middle A: 0.6562
4. Find the area of the indicated region under the standard normal curve. -1.13/2.03 left/right A: 0.1504
5. Find the area under the standard normal curve to the left of z = 1.5. A: 0.9332
6. Find the area under the standard normal curve to the left of z = 1.25 A: 0.8944
7. Find the area under the standard normal curve to the right of z = 1 A: 0.1587
8. Find the area under the standard normal curve to the right of z = -1.25. A: 0.8944
9. Find the area under the standard normal curve between z = 0 and z =3. A: 0.4987
10. Find the area under the standard normal curve between z = 1 and z = 2 A: 0.1359
11. Find the area under the standard normal curve between z = -1.5 and z = 2.5 A: 0.9270
12. Find the area under the standard normal curve between z = 1.5 and z = 2.5 A: 0.0606
13. Find the area under the standard normal curve between z = -1.25 and z = 1.25. A: 0.7888
14. Find the sum of the areas under the standard normal curve to the left of z = -1.25 and to the right A: 0.2112
**Find the probability of z occurring in the indicated region
29. picture 1.82 A: 0.9656
30. picture -0.59 A: 0.2776
31. picture -1.33 A: 0.9082
32. picture 1.75 A: 0.0401
33. picture -2/3 A: 0.9772
34. picture 1.50 A: 0.4332
35. Use the standard normal distribution to find P(0 < z < 2.25). A: 0.4878
36. Use the standard normal distribution to find P(-2.25 < z < 0). A: 0.4878
37. Use the standard normal distribution to find P(-2.25 < z < 1.25). A: 0.8822
38.  Use the standard normal distribution to find P(-2.50 < z < 1.50). A: 0.9270
39. Use the standard normal distribution to find P(z < -2.33 or z > 2.33) A: 0.0198
40. For the standard normal curve, find the z-score that corresponds to the third quartile. A: 0.67
41. For the standard normal curve, find the z-score that corresponds to the first quartile. A: -0.67
42. For the standard normal curve, find the z-score that corresponds to the first decile. A:  -1.28
43. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An individualʹs IQ score is found to be 110. Find the z-score corresponding to this value. A: 0.67
44.  IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An individualʹs IQ score is found to be 90. Find the z-score corresponding to this value A: -0.67
45. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An individualʹs IQ score is found to be 120. Find the z-score corresponding to this value A: 1.33
46. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. Find the IQ score that corresponds to a z-score of 1.96. A: 129.4
47.  IQ test scores are normally distributed with a mean of 102 and a standard deviation of 19. An individualʹs IQ score is found to be 124. Find the z-score corresponding to this value. A: 1.16
48. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 12. An individualʹs IQ score is found to be 127. Find the z-score corresponding to this value. A: 2.25
49. The lengths of pregnancies of humans are normally distributed with a mean of 268 days and a standard deviation of 15 days. Find the probability of a pregnancy lasting more than 300 days. A: 0.0166
50. The lengths of pregnancies of humans are normally distributed with a mean of 268 days and a standard deviation of 15 days. Find the probability of a pregnancy lasting less than 250 days. A: 0.1151
51. The distribution of cholesterol levels in teenage boys is approximately normal with μ = 170 and σ = 30 (Source: U.S. National Center for Health Statistics). Levels above 200 warrant attention. Find the probability that a teenage boy has a cholesterol level greater than 200. A: 0.1587
95. Assume that the heights of women are normally distributed with a mean of 63.5 inches and a standard deviation of 2.5 inches. Find Q3, the third quartile that separates the bottom 75% from the top 25%. A: 65.2
96. The body temperatures of adults are normally distributed with a mean of 98.6 ° F and a standard deviation of 0.19° F. What temperature represents the 95th percentile? A: 98.91 F
97.  In a certain normal distribution, find the standard deviation σ when μ = 50 and 10.56% of the area lies to the right of 55. A: 4
98. In a certain normal distribution, find the mean μ when σ = 5 and 5.48% of the area lies to the left of 78. A: 86
100. A tire company finds the lifespan for one brand of its tires is normally distributed with a mean of 48,400 miles and a standard deviation of 5000 miles. If the manufacturer is willing to replace no more than 10% of the tires, what should be the approximate number of miles for a warranty?
A: 42,000